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70 lines
2.4 KiB
70 lines
2.4 KiB
# MySQL Bootcamp
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## Lesson Objectives
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1. What does SQL Stand for? What is it?
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1. What is a DB?
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1. What are the different ways to store data?
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1. What are the advantages of a database?
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1. Diagram MySQL structure
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1. Connect to MySQL
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1. Create a DB
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1. CRUD
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1. LIKE
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1. AND/OR
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1. DISTINCT
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1. ORDER BY
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1. OFFEST/LIMIT
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1. ALTER
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1. GROUP BY
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```sql
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SHOW DATABASES;
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CREATE DATABASE users;
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USE users;
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CREATE TABLE employees (NAME VARCHAR(20), age INT);
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DESCRIBE employees;
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-- CRUD
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INSERT INTO employees (NAME, age) VALUES ('Matt' , 34);
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SELECT age FROM employees;
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SELECT * FROM employees;
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UPDATE employees SET weight = 300 WHERE first_name = 'Bill';
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DELETE FROM employees WHERE first_name = "Bill";
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SELECT * FROM employees WHERE NAME LIKE "%Charlie%" OR age = 80;
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SELECT DISTINCT name FROM employees WHERE age > 45;
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SELECT * FROM employees WHERE age != 63;
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SELECT * FROM employees ORDER BY age DESC;
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SELECT * FROM employees ORDER BY age ASC LIMIT 2;
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SELECT * FROM employees ORDER BY age ASC LIMIT 2 OFFSET 1;
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SELECT * FROM employees ORDER BY age DESC, NAME ASC;
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ALTER TABLE employees ADD COLUMN weight FLOAT;
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ALTER TABLE employees DROP COLUMN height;
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ALTER TABLE employees ADD COLUMN height FLOAT AFTER NAME;
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ALTER TABLE employees MODIFY COLUMN height FLOAT AFTER age;
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ALTER TABLE employees ADD COLUMN id INT FIRST;
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ALTER TABLE employees ADD COLUMN dob DATETIME;
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ALTER TABLE employees CHANGE dob date_of_birth DATETIME;
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ALTER TABLE companies ADD COLUMN id INT NOT NULL AUTO_INCREMENT PRIMARY KEY FIRST;
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SELECT COUNT(*), age FROM employees GROUP BY age;
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SELECT COUNT(*) FROM employees GROUP BY age;
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SELECT SUM(age) FROM employees GROUP BY age;
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SELECT AVG(age) FROM employees;
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SELECT MIN(age) FROM employees;
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SELECT MAX(age) FROM employees;
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SELECT GROUP_CONCAT(age) FROM employees;
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SELECT GROUP_CONCAT(age) FROM employees, name;
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SELECT * from employees FULL JOIN companies;
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SELECT * FROM employees JOIN companies ON employees.`employer_id` = companies.`id`;
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SELECT * FROM employees RIGHT OUTER JOIN companies ON employees.`employer_id` = companies.id WHERE employees.`employer_id` IS NULL;
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SELECT * FROM employees LEFT OUTER JOIN companies ON employees.`employer_id` = companies.id WHERE employees.`employer_id` IS NULL;
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SELECT employees.*, companies.`name` FROM employees INNER JOIN companies ON employees.`employer_id` = companies.id;
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SELECT e.*, c.name AS company_name FROM employees AS e INNER JOIN companies AS c ON e.employer_id = c.id;
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```
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